Ëæ×ÅÏÖ´ú¿ÆѧÊÖÒÕµÄÉú³¤£¬Ïð½ºÉú²úÊÖÒÕÒ²Ô½À´Ô½¶àÕ¹ÏÖ³ö¸ßÐÂÊÖÒÕµÄÉú³¤¡£Ï𽺸ßЧ¿ìËÙÁò»¯¼ÁºÍÔö½ø¼ÁµÄ·¢Ã÷£¬µçÏßµçÀ¿ìËÙÁò»¯Ò²³ÉΪÏÖʵ¡£½ÓÁ¬Áò»¯ÊÇ´Ó¼·ÏðºÍ¹ÞʽÁò»¯Ñݱä¶øÀ´£¬½ÓÁ¬Áò»¯ÓÐÐí¶àÓŵã£¬Éú²ú¹¦Âʸß£¬µçÏßµçÀ±í¹Û±È¹Å°å¹¤ÒÕ´ó´óÌá¸ß£¬Í­µ¼Ìå²»»áÑõ»¯µÈ¡£ÓùŰ幤ÒÕÉú²úµÄÏðÌ×µçÀÂÒ»Ñùƽ³£²»¿ÉºÍ¸ßµÈ¼ÒÓõçÆ÷ÅäÌ×£¬ÆäÖ÷ÒªÔµ¹ÊÔ­ÓÉÊǵçÀµÄÍâ¹ÛÇ·ºÃ£¬Í­Ë¿Ñõ»¯ÑÏÖØ£¬²»¿ÉºÍ¼ÒÓõçÆ÷ÅäÌ×£¬Ò»Ñùƽ³£ÓÃËÜÁÏÈíµçÀÂÈ¡´ú¡£Ëæ×ÅÖйú¼ÓÈëWTO£¬ÖйúµÄ²úÆ·±ê×¼Ò²ËùÓа´¹ú¼ÊIEC±ê×¼Ò»ÖÂ£¬Ðí¶à¼ÒÓõçÆ÷µÄ¹©µçµçÔ´Ïß¹æÔòÓÐÐëҪʹÓÃÏðÌ×µçÀÂ£¬Èç¿Õµ÷Æ÷ÓõÄÊÒÄÚÍâÅþÁ¬Ï߾͹æÔòÓÐÐëÒªÓÃ245IEC57£¨YZW£©ÏðÌ×ÈíµçÀ¡£Òò´Ë£¬Ìá¸ßÏðÌ×ÈíµçÀµÄÍâ¹ÛÖÊÁ¿£¬ÊÇÄ¿½ñ¼±Ðè½â¾öµÄÏÖʵÎÊÌâ¡£Á¬¼ÌÁò»¯ÊÇÒ»ÖÖеÄÏðÌ×µçÀ¼ӹ¤ÒªÁì£¬±¾ÎÄͨ¹ý¶ÔÏðÌ×µçÀÂÉú²úÀú³ÌÖеÄһЩ¹¤ÒÕ²ÎÊýÌÖÂÛ£¬ÍƵÀ³öÒ»ÕûÌ×µÄÁòÐøÁò»¯¹¤ÒÕ²ÎÊý£¬Ò»Ö±Ìá¸ßÏðÌ×µçÀµIJúÆ·ÖÊÁ¿£¬¹©µçÀÂÐÐÒµµÄÙÉÐÐÃDzο¼¡£

2 ±ê×¼µÄ¶Ï¶¨

Ò»Ñùƽ³£½ÓÁ¬Áò»¯»ú×éÊÖÒչ淶¶¼¹æÔòÄ£¾ß³ß´ç¹æÄ££¬¼´¹æÔòÁËģо¡¢Ä£Ì׺ÜС¿×¾¶£¬ÕâÊǶ϶¨±ê×¼µÄƾ֤֮һ¡£ÁíÍâ£¬»¹¹æÔòÂݸËתËÙ¹æÄ££¬¼·ÏðʱÂݸËתËÙµÍÓÚ¹æÔòתËÙ£¬Ïð½ºËÜÐÔ²»ÔȳÆ£¬Á÷¶¯ÐÔ²î£¬¼·³öÁ¿²»·óÎȹÌ£¬µçÀ¼ӹ¤ÄÑÌâ£¬»úÍ·ÄÚѹÁ¦ºÜ´ó£¬ÈÝÒ׶¥»µ»úÍ·¡£ÈôÁè¼Ý¹æÄ££¬Ï𽺼·³öÁ¿È±·¦£¬Ö»ÄܽµµÍ³öÏßËÙÂÊÀ´Ìî²¹£¬Ó°ÏìÉú²ú¹¦ÂÊ¡£

3  ÂݸËתËÙºÍÇ£ÒýËÙÂʵĶ϶¨

ÂݸËתËÙºÍÇ£ÒýËÙÂʾöÒéÁËÉú²ú¹¦ÂʺÍÖÆÆ·µÄÍ⾶¡¢Íâ¹Û¡£¶Ï¶¨ÂݸËתËÙºÍÇ£ÒýËÙÂʵĻùÀ´Ô´ÀíÊÇÎïÁÏƽºâÔ­Àí£¬¼´Âݸ˼·³öµÄÏð½ºÁ¿£¬ÕýºÃ±»Ç£Òý³öÀ´µÄÖÆÆ·°ü¸²ËùÐèÇóµÄÏð½ºÁ¿ÏàµÈ¡£

Ò»Ñùƽ³£µØ˵£¬¶Ï¶¨Âݸ˺ÍÇ£ÒýËÙÂÊʱ£¬Ïȶ¨³öÇ£ÒýËÙÂÊ£¬¼´Áò»¯Ê±¿Ì£¬ËüÊǾöÒéÖÆÆ·¸÷Ïî»úеÎïÀíÐÔÄܵÄÖ÷ÒªÒòËØ£¬±¾ÎĽ«×÷ÏêϸÏÈÈÝ¡£

½ÓÁ¬Áò»¯¼·Ïð»úÂݸ˶¼½ÓÄɳ¤¾¶±È12£º1ÒÔÉϵÄËÜ»¯ÂݸË£¬ÂݸËÓëͲÌåÖ®¼ä»ØÁÏÁ¿Ð¡£¬ÂݸËתËÙÓë¼·³öÁ¿»ù±¾³ÉÕý±È£¬¼´³ÉÏßÐÔ¹Øϵ¡£

ÀýÈç£¬Ä³¼·Ïð»ú×éÊÖÒչ淶ÖйæÔò£¬ÂݸËתËÙΪ10¡«50rpm/min,ºÜ´ó¼·³öÁ¿Îª120kg/h¡£Æ¾Ö¤ÕâЩÊý¾ÝÄܹ»ÖÆ×÷ÂݸËתËٺͼ·³öÁ¿¹Øϵͼ£¨¼ûͼ1£©¡£

0      0.2       0.4        0.6        0.8       1.0       1.2        1.4       1.6      1.8     2.0

¹«½ï/·Ö

                          ͼ  1

ÀýÈç£¬Ä³²úÆ·¼·»¤Ì×£¬ÀíÂÛºËË㻤Ì×ÓÃÁÏÁ¿Îª78.7 kg/km,³öÏßËÙÂÊΪ20m/min,Äܹ»ºËËã³öÿ·ÖÖÓµÄÓÃÁÏÁ¿£º

ÓÃÁÏÁ¿=20¡Á78.7¡Â1000=1.574  kg/min

ƾ֤ÎïÁÏƽºâÔ­Àí£¬Ï𽺼·³öÁ¿Ò²ÐèÇó1.574  kg/min£¬²éͼ1Äܹ»µÃ³ö£¬ÂݸËתËÙΪ39ת/·Ö×óÓÒ£¬ÔÚ×°±¸¹æ·¶¹æÔòµÄתËÙ¹æÄ£ÄÚ£¬ÇкÏ×°±¸ÊÖÒչ淶¡£Æ¾Ö¤ÕâÒ»ÒªÁì£¬Äܹ»¶Ï¶¨³ö¸Ã×°±¸Éú²úÖÖÖÖ±ê×¼µÄÂݸËתËÙºÍÇ£ÒýËÙÂÊ¡£

4 »úÉí»úͷζȵĶ϶¨

»úÉí½øÁ϶ÎζÈÒ»Ñùƽ³£¿ØÖƵÍÒ»µã£¬Ô¼Äª30-40¶È£¬Î¶ȹý¸ßÓлØÁÏÕ÷Ïó£¬ÇÒÏð½ºÒ×½¹ÉÕ¡£»úͷζÈҪƾ֤Ïð½ºÖÖÀàºÍ½ºÁÏÔÚ»úÌåÄÚÍ£Áôʱ¿ÌÀ´¶Ï¶¨£¬Ò»Ñùƽ³£ÔÚ60-70¶È¡£ÖÐÐĸ÷¶ÎζÈ£¬´Ó»úͷζÈÖ𲽵ݼõµÄÒªÁì¶Ï¶¨£¬Ò»Ñùƽ³£ÔÚ40-50¶È¡£½ÓÁ¬Áò»¯½øÁÏÒ»Ñùƽ³£½ÓÄÉÀäιÁÏ£¬ÏðÒ³ºñ¶È¿ØÖÆÔÚ0.5-1.0mmÖ®¼ä¡£ÈôÊǽÓÄÉÈÈιÁÏ£¬ÇгÉÌõ×´£¬Ò²ÊǺܺõÄ¡£

5 ÕôÆûѹÁ¦ºÍ³öÏßËÙÂʵĶ϶¨

ÕôÆûѹÁ¦ºÍ³öÏßËÙÂÊÊÇÁ¬Áò²Ù×÷µÄÖ÷Òª²ÎÊý£¬Æä¹Øϵµ½²úÆ·»úеÎïÀíÐÔÄÜ©pÍâ¹ÛÖÊÁ¿©pÉú²ú¹¦ÂʵÈ¡£

»¯Ñ§·´Ó¦¶¯Á¦Ñ§Ö¸³ö£¬µ±·´Ó¦Å¨¶ÈÎȹ̵ÄÇéÐÎÏÂ£¬Î¶ÈÿÉý¸ß10K£¬·´Ó¦ËÙÂÊԼĪÔöÌí2¡«3±¶¡£°¢ÂØÄáÎÚ˹×ܽáÁËÐí¶àµÄʵÑéÊÂʵ£¬Ö¸³ö·´Ó¦ËÙÂʳ£ÊýºÍ          ζȵĹØϵ£º

           k=A¡¤e-E/RT     

ʽÖУº     k-----·´Ó¦ËÙÂʳ£Êý£»

E-----·´Ó¦»î»¯ÄÜ£»

R-----ÆøÌå³£Êý£»

T-----ÓÐÓÃζÈ£¬K£»

e-----×ÔÈ»¶ÔÊýµÄµ×£¨e=2.718£©¡£

¸Ã¹«Ê½ÔÚÏÖʵʹÓÃÖÐÓÐÄÑÌâ¡£ÊÊÓõÄÏ𽺷´Ó¦ËÙÂÊÓëζÈÖ®¼äµÄ¹Øϵ¿ÉÓÃÏÂʽÀ´ºËË㣺

           V2=V1 2 0.1(t2-t1)

         V1------t1 Ê±µÄ·´Ó¦ËÙÂÊ£»

         V2------t2 Ê±µÄ·´Ó¦ËÙÂÊ£»

      t1,t2-------  ζȣ¨¡æ£©£»

         2--------ζÈϵÊý

ÕâЩÀíÂÛ¶¼Ìá³ö£¬Ïð½ºÁò»¯Î¶ÈÿÔöÌí10¡æ£¬Áò»¯ËÙÂÊÔöÌíÒ»±¶£¬¼´Áò»¯Ê±¿ÌËõ¶ÌÒ»±¶¡£ÎÒÃÇÒ»Ñùƽ³£¶¼ÓйÞʽÁò»¯µÄÉú²úºÍÊÖÒÕ²ÎÊý£¬¶ÔÒ»¸ö³ÉÊìÏð½ºÅä·½Ó¦¸ÃºÜÏàʶÆäÖÖÖÖÁò»¯²ÎÊý¡£Æ¾Ö¤¹ÞʽÁò»¯±¥ºÍÕôÆûѹÁ¦ÏµÄζÈ£¬ÍÆËã³öÁ¬Áò»¯Ê±±¥ºÍÕôÆûѹÁ¦£¬ÔÙÇó³öÁò»¯Ê±¿ÌºÍ³öÏßËÙÂÊ¡£

ÀýÈç£¬Ä³½ÓÁ¬Áò»¯»ú×é£¬½ÓÁ¬Áò»¯¹ÜµÀ³¤¶ÈΪ50Ã×£¬Éú²úµçÀÂÍ⻤Ì×£¬Æ¾Ö¤³ÉÊìµÄÏðƤÅä·½Áò»¯¹¤ÒÕ²ÎÊý£¬4kg/cm2£¨151¡æ£©ÏÂ£¬Áò»¯Ê±¿ÌΪ15·ÖÖÖ£¬ÈôÊÇÔÚ½ÓÁ¬Áò»¯»ú×éÉÏÉú²ú£¬»¤Ì׳öÏßËÙÂÊΪ25Ã×£¬½ÓÁ¬Áò»¯µÄÕôÆûѹÁ¦Îª¼¸¶à¡£

ÏȺËËã½ÓÁ¬Áò»¯ËùÐèÇóµÄʱ¿ÌΪ£º50/25=2·ÖÖÓ¡£Æ¾Ö¤Î¶ÈÿÉÏÉý10¶È£¬Áò»¯Ê±¿ÌËõ¶ÌÒ»°ëµÄ¹Øϵ¡£ºËËã³öʱ¿Ì±¶ÊýÊÇ3±¶¡£¼´Î¶ÈÐèÇóÌáÉý30¶È¡£Ò²¾ÍÊǽÓÁ¬Áò»¯µÄζÈΪ181¶È¡£

½ÓÁ¬Áò»¯µÄÕôÆûѹÁ¦Ô½¸ßÁò»¯ËÙÂʾÍÔ½¿ì£¬Éú²ú¹¦ÂÊÒ²»á´óÌá¸ß¡£Êµ¼ù֤ʵ£¬²¢²»ÊÇÕôÆûѹÁ¦ÄÜÎÞÏÞµØÉý¸ß£¬À´Ìá¸ß½ÓÁ¬Áò»¯µÄËÙÂÊ¡£

Á¬ÁòÕôÆûѹÁ¦£¨¼´Áò»¯Î¶ȣ©ºÜ¸ßÖµÔõÑù¶Ï¶¨¡£¾­ÆÊÎö£¬ÖÆÆ·ÔÚÁ¬Áò¹ÜÁò»¯Ê±£¬ÖÆÆ·Íⲿ¾­ÊܽϸߵÄÕôÆûѹÁ¦£¬Í¬Ê±ÔâÊܽϸߵÄÁò»¯Î¶È£¬ÖÆÆ·ÄÚ²¿µÄ¿ÕÆøÉÙÁ¿µÄË®·ÝµÍ·Ðµã»Ó·¢·ÝÒÔ¼°Áò»¯Ê±±¬·¢µÄÆøÌå»áÅòÕÍ£¬ÔÚÁò»¯¹ÜÖÐ£¬ÄÚÍâѹÁ¦Ï໥µÖÏû£¬Ò»Ñùƽ³£²»»á±¬·¢ÅòÕÍ¡£³öÖÕ¶ËÃÜ·â½øÈ볣ѹÏÂ£¬ÖÆÆ·ÄÚ²¿À´È±·¦Ñ¸ËÙÀäÈ´£¬ÈÔÈ»´¦ÔÚ¸ßÎÂÅòÕÍ״̬£¬ÄÚ²¿µÄÆøÌå»áѸËÙÅòÕ͵Ä£¬ÈôÊÇÖÆÆ·µÄ¾¶ÏòÓ¦Á¦¾­Êܲ»×¡ÄÚ²¿Ñ¹Á¦£¬¾Í»áÆðÅÝ£¬ÑÏÖصĻῪÁÑ¡£ÈôÏ𽺻ìÁ¶²»ÔȳÆ£¬ÕâÖÖÕ÷Ïó¸üΪÏÔ×Å¡£

ÈôÊÇÖÆÆ·³öÖÕ¶ËÃÜ·âµÄÒ»»á¶ù£¬°ÑÖÆÆ·×÷ΪѹÁ¦ÈÝÆ÷À´´¦Öóͷ££¬±¾ÎÄ×ܽá³öÒ»Ì׺ܸßÁ¬ÁòÕôÆûѹÁ¦¹«Ê½£º

           ¦Ä=P¡¤ DÄÚ/£¨2[¦Ò] t- P£©

ʽÖÐ £º     ¦Ä  ------ÖÆÆ·¿ØÖƵĺܱ¡µãºñ¶È£¬mm  £»

             P  ------ºÜ¸ßÁò»¯ÕôÆûѹÁ¦£¬MPa £»

             DÄÚ------ÖÆÆ·¼·ÏðÇ°µÄÍ⾶£¬mm £»

           [¦Ò] t -----Áò»¯Î¶ÈϵÄÖÆÆ·¾¶ÏòÓ¦Á¦£¬N/ mm 2 ¡£

Æä¼ä£¬Áò»¯Î¶ÈÏÂÏ𽺵ľ¶ÏòÓ¦Á¦  [¦Ò] t  £¬±ÈÖÆÆ·µÄÖáÏòԭʼÀ©ÕÅÇ¿¶ÈµÍ¡£¿ÉÓÃÆðÅÝʱµÄÓ¦Á¦£¬À´ºËËãÆðÅÝʱºÜ¸ßÁò»¯ÕôÆûѹÁ¦£¬¿ªÁÑʱµÄÓ¦Á¦£¬À´ºËËãÆðÅÝʱºÜ¸ßÁò»¯ÕôÆûѹÁ¦£¬¿ªÁÑʱµÄÓ¦Á¦£¬À´ºËË㿪ÁÑʱºÜ¸ßÁò»¯ÕôÆûѹÁ¦¡£¿É˼Á¿ÓÃÖÆÆ·µÄ¶¨É쿹ÕÅÇ¿¶ÈºÍ¸ßÎÂÏÂÏð½ºÈȱäÐÎ£¬ÒÔ¼°¾¶Ïò¿¹ÕÅÇ¿¶È½ÏСµÈ×ÛºÏÒòÏòÀ´¶Ï¶¨  [¦Ò] t ¡£Æ¾Ö¤Áò»¯ºÜ¸ßÕôÆûѹÁ¦¼´Áò»¯Î¶È£¬Äܹ»ÍÆËã³öÁò»¯Ê±¿Ì£¬¼´ºÜ´ó³öÏßËÙÂÊ¡£Í¬Ê±£¬»¹ÒªË¼Á¿ÀÂоåÐÒ£Ìî³äϸÃÜˮƽ¡£